If your single lottery ticket has say 49 numbers and the winning number sequence is 6 numbers in length the odds of winning are 49!/((49-6)! x 6!) = 13,983,816 to 1 odds.

If a second lottery ticket is purchased with a different winning sequence then all that has happened is that you have purchased another 6 number sequence reducing your odds to (49!/((49-6)! x 6!))-1 = 13,983,815 to 1 odds

If the aim was to get a 5 number winning sequence from 49 numbers then the odds of winning are 49!/((49-5)! x 5!) = 1,906,884 to 1 odds

Actually what you are better of doing is ensuring that if you place a single line i.e. a single $1 bet with odds of say 13,983,816 at least make sure the winning pot of money total is actually greater than the probability of winning and then only placing just the single 1$ bet. i.e. if the pot rolls over.