I was curious what the ratio of these two chemicals should be to achieve complete combustion but couldn't find anything online, so I just ran the stoichiometry calculations and came up with the following:

Potassium Permanganate____KMnO4_______158.04 g/mol____2.70g/cm^3
Glycerin__________________C3H5(OH)3_____92.09 g/mol____1.26g/cm^3

Balanced chemical equation:

14KMnO4 + 4C3H5(OH)3 --> 7K2CO3 + 7Mn2O3 + 5CO2 + 16H2O

Reactants:

20.0g_____________KMnO4
3.33g_____________C3H5(OH)3

Products:

8.75g_____________K2CO3
9.99g_____________Mn2O3
1.99g_____________CO2
2.61g_____________H2O

Conversions:

1 cm^3 = 1 mL = 0.034 fl oz____________1 oz = 28.35g

Therefore:

20g KMnO4________=______0.705 oz______=______0.25 fl oz
3.33g C3H5(OH)3___=______0.117 oz______=______0.09 fl oz

Based on this ratio I will probably carry a 1 fl oz bottle of potassium permanganate along with a 1/2 fl oz bottle of glycerine (I have plenty of both of these sizes on hand) and know that I could start four fires with this quantity.

Perhaps one of the resident chemists or chemical engineers can double check my numbers when they have a few moments.

Jim